3((3/2)y^2)^2+2y=0

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Solution for 3((3/2)y^2)^2+2y=0 equation: 



3((3/2)y^2)^2+2y=0



Domain of the equation: 2)y^2)^2!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

3((+3/2)y^2)^2+2y=0

We add all the numbers together, and all the variables

2y+3((+3/2)y^2)^2=0

We multiply all the terms by the denominator


2y*2)y^2)^2+3((+3=0

Wy multiply elements

4y^2+3=0

a = 4; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·4·3
Δ = -48
Delta is less than zero, so there is no solution for the equation

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